Timeline for Differentiating an integral that grows like log asymptotically
Current License: CC BY-SA 4.0
9 events
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Jan 14, 2019 at 12:53 | vote | accept | random_person | ||
Jan 14, 2019 at 12:45 | comment | added | Mateusz Kwaśnicki | @random_person: I just started to type when Iosif Pinelis gave esentially the same construction. I can oly add that what I meant in my first comment was Theorem 3.6.8 in the BGT book, which gives a necessary and sufficient condition for the desired asymptotics of $f$ in terms of its primitive function. See also Sections 3.7.1–3.7.2 therein. | |
Jan 14, 2019 at 12:19 | comment | added | random_person | @MateuszKwaśnicki Thanks, I am looking forward to your answer. | |
Jan 14, 2019 at 10:48 | comment | added | Mateusz Kwaśnicki | Original asymptotic equation is equivalent to $f$ being in the right de Haan class. Two-sided estimate would correspond to de Haan's analogue of $O$-regular variation, I think, and it does not follow automatically. The counter-example is less explicit, though, I will type it later today on a computer, if you like. | |
Jan 14, 2019 at 9:40 | comment | added | random_person | What about bounds? Is it possible to show that there exists some $C > 0$ such that $\frac{1}{Ct} \le f(t) \le \frac{C}{t}$ for $t$ sufficiently large? | |
Jan 14, 2019 at 9:33 | history | edited | Raziel | CC BY-SA 4.0 |
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Jan 14, 2019 at 9:23 | history | edited | Raziel | CC BY-SA 4.0 |
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Jan 14, 2019 at 9:05 | history | edited | Raziel | CC BY-SA 4.0 |
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Jan 14, 2019 at 9:00 | history | answered | Raziel | CC BY-SA 4.0 |