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Jun 13, 2014 at 5:38 history edited Mikhail Bondarko CC BY-SA 3.0
edited body; edited title
Jul 16, 2010 at 0:54 comment added BCnrd Assume $X$ connected, hence irred. Assume $f$ dominant, or else the complement of closure of the image does the trick. Thus, $S$ is irred (and presumably you assume quasi-compact, so noetherian since excellent). By generic flatness, can assume $f$ flat by passing to dense open in $S$. Generic fiber is regular, so if generic point of $S$ is char. 0 then generic fiber is smooth. Then by flatness, $f$ is smooth over dense open (EGA IV$_4$, sec. 17 somewhere), so win without excellence. False without generic char. 0 (Speyer's example). Final equivalence unclear (I guess false); feels useless.
Jul 16, 2010 at 0:45 vote accept Mikhail Bondarko
Jul 16, 2010 at 0:39 answer added David E Speyer timeline score: 14
Jul 16, 2010 at 0:07 history edited Mikhail Bondarko CC BY-SA 2.5
added 155 characters in body; added 14 characters in body
Jul 15, 2010 at 23:15 history asked Mikhail Bondarko CC BY-SA 2.5