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Jan 12, 2019 at 19:34 comment added მამუკა ჯიბლაძე ...and you get $\text{Tor}$ on the right since $\text{Hom}(-,\mathbb Q/\mathbb Z)$ is exact. Fine.
Jan 12, 2019 at 14:14 vote accept Sean Eberhard
Jan 12, 2019 at 14:14 comment added Sean Eberhard Very slick. Nice.
Jan 12, 2019 at 14:01 comment added Jeremy Rickard @მამუკაჯიბლაძე $\text{Hom}(-,\text{Hom}(F,\mathbb{Q}/\mathbb{Z}))\cong\text{Hom}(-\otimes F,\mathbb{Q}/\mathbb{Z})$. I’m just applying the first right derived functor of each side to $H$.
Jan 12, 2019 at 13:06 comment added მამუკა ჯიბლაძე Is the last isomorphism obvious? I mean, I could probably easily prove it, but...
Jan 12, 2019 at 12:22 history answered Jeremy Rickard CC BY-SA 4.0