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Feb 19 at 0:09 answer added TheSimpliFire timeline score: 2
Jan 10, 2019 at 15:36 comment added Gerry Myerson Heuristics suggest that $x^y+y^x=z^2$ with $\gcd(x,y)=1$ and $x^{-1}+y^{-1}+2^{-1}<1$ has only finitely many solutions (but it's only a heuristic, and only applies when $\gcd(x,y)=1$).
Jan 10, 2019 at 3:24 history edited Alexey Ustinov CC BY-SA 4.0
deleted 11 characters in body
Jan 10, 2019 at 2:59 history edited Martin Sleziak CC BY-SA 4.0
added a top-level tag; https://meta.mathoverflow.net/questions/1457/why-are-mo-tags-formatted-as-they-are
Jan 10, 2019 at 2:45 review First posts
Jan 10, 2019 at 3:25
Jan 10, 2019 at 2:43 history asked don bright CC BY-SA 4.0