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Jan 8, 2019 at 17:15 comment added Noah Schweber @PierrePC Indeed, and that's actually how I (mis)read the question. :P
Jan 8, 2019 at 17:15 history edited Noah Schweber CC BY-SA 4.0
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Jan 8, 2019 at 16:34 comment added Pierre PC Not a fascinating remark, but the proof also holds with a limsup in the definition of $\mu$.
Jan 8, 2019 at 16:11 comment added Noah Schweber @Wojowu You're quite right, I remembered it incorrectly.
Jan 8, 2019 at 16:10 history edited Noah Schweber CC BY-SA 4.0
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Jan 8, 2019 at 16:09 comment added Wojowu I don't think Szemeredi gives us the result - the infinitely many arithmetic progressions might all have different differences and not be translates of one another.
Jan 8, 2019 at 15:54 history edited Noah Schweber CC BY-SA 4.0
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Jan 8, 2019 at 15:54 vote accept Dominic van der Zypen
Jan 8, 2019 at 15:54 comment added Dominic van der Zypen Beautiful @NoahSchweber - and lightning fast!
Jan 8, 2019 at 15:53 comment added Noah Schweber @Wojowu Yeah, I caught that at the same time.
Jan 8, 2019 at 15:52 history edited Noah Schweber CC BY-SA 4.0
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Jan 8, 2019 at 15:50 comment added Wojowu In the third paragraph you first write $\mu(B)=\epsilon$, and immediately after $\mu(B)>\epsilon$. I think you want the first equality to be an inequality as well.
Jan 8, 2019 at 15:48 history edited Noah Schweber CC BY-SA 4.0
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Jan 8, 2019 at 15:44 history undeleted Noah Schweber
Jan 8, 2019 at 15:43 history deleted Noah Schweber via Vote
Jan 8, 2019 at 15:42 history answered Noah Schweber CC BY-SA 4.0