Timeline for Description of p-adics tensor the reals
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Feb 27 at 2:58 | history | bounty ended | Noah Schweber | ||
| S Feb 27 at 2:58 | history | notice removed | Noah Schweber | ||
| Feb 21 at 1:24 | answer | added | Will Sawin | timeline score: 4 | |
| S Feb 21 at 1:14 | history | bounty started | Noah Schweber | ||
| S Feb 21 at 1:14 | history | notice added | Noah Schweber | Draw attention | |
| Feb 21 at 0:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 14, 2019 at 23:00 | comment | added | Marty | It's a ring whose Krull dimension is the continuum... eek! | |
| Jan 14, 2019 at 21:35 | answer | added | George C. Modoi | timeline score: -3 | |
| Jan 8, 2019 at 14:31 | comment | added | abx | @Victor Petrov: $\mathbb{R}\otimes _{\mathbb{Z}}\mathbb{Z}[[T]]\neq\mathbb{R}[[T]]$. | |
| Jan 8, 2019 at 14:22 | comment | added | Victor Petrov | The following observation may be helpful: ${\mathbb Z}_p\simeq {\mathbb Z}[[T]]/(T-p)$, so the tensor product is ${\mathbb R}[[T]]/(T-p)$. | |
| Jan 8, 2019 at 13:54 | comment | added | Laurent Moret-Bailly | @DenisT. $\mathbb{Z}_p\otimes\mathbb{R}$ is certainly not a field. | |
| Jan 8, 2019 at 1:28 | history | asked | Time suspect | CC BY-SA 4.0 |