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Jan 4, 2019 at 15:01 vote accept John Klein
Jan 4, 2019 at 14:40 history edited John Klein CC BY-SA 4.0
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Jan 4, 2019 at 10:29 answer added Najib Idrissi timeline score: 6
Jan 3, 2019 at 16:45 comment added John Klein @DanPetersen in the symmetric sequence context (that was what I was missing). I was used to modules over an operad in spaces. Thanks.
Jan 3, 2019 at 16:42 comment added Dan Petersen Yes: this is called a right module over an operad.
Jan 3, 2019 at 16:33 history edited John Klein CC BY-SA 4.0
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Jan 3, 2019 at 16:32 comment added John Klein @TylerLawson so, does that mean the symmetric sequence forms a module (or algebra) over the disk-embedding operad?
Jan 3, 2019 at 16:27 comment added Tyler Lawson I believe that this is a right action of disc-embedding operad $\{E(k,D^p)\}_{k \geq 0}$ on the symmetric sequence $\{E(k, P)\}_{k \geq 0}$; I think I have seen this in a talk of Turchin's on embedding calculus.
Jan 3, 2019 at 16:22 history edited John Klein CC BY-SA 4.0
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Jan 3, 2019 at 16:13 history asked John Klein CC BY-SA 4.0