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Aug 21, 2010 at 7:47 comment added Robin Chapman No, see Skoruppa, Nils-Peter, A quick combinatorial proof of Eisenstein series identities., J. Number Theory 43 (1993), no. 1, 68--73 for a non-analytic proof.
Aug 11, 2010 at 23:04 comment added David Corwin It follows from the fact that $E_4^2 = E_8$, which follows from the dimension formulas for spaces of modular forms of a given weight.
Aug 11, 2010 at 18:19 comment added Derek Jennings I just found the result you gave on wikipedia and it is derived using Eisenstein series, which is how I obtained my identities for the tau function, so I believe my proof of this result is pretty similar to what you had in mind.
Aug 11, 2010 at 18:04 comment added Derek Jennings This result drops out easily from a couple of identities for Ramanujan's tau function that I published in my 1993 thesis: \tau(n) = 60 \sum_{k=0}^n (n-3k)(2n-3k)s_3(k)s_3(n-k) and \tau(n)=n^2s_7(n) – 540 \sum_{k=1}^{n-1} k(n-k)s_3(k)s_3(n-k), where s_3(0)=1/240 (for s read \sigma). What proof are you referring to? Thanks.
Jul 15, 2010 at 10:57 history answered David Corwin CC BY-SA 2.5