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Dec 30, 2018 at 16:06 comment added Nico A I saw this in the hot questions list and went, "Huh! We worked on something similar at Hampshire but didn't get far.". Lo and behold :D
Dec 30, 2018 at 5:31 comment added YCor This is known as "solvable uniform (subgroup) membership problem".
Dec 30, 2018 at 5:25 history edited YCor CC BY-SA 4.0
fixed Schreier spelling
Dec 30, 2018 at 4:55 vote accept Milo Brandt
Dec 30, 2018 at 4:32 answer added Andy Putman timeline score: 18
Dec 30, 2018 at 4:27 comment added Dima Pasechnik oops, right. sorry for noise.
Dec 30, 2018 at 4:23 comment added Andy Putman @DimaPasechnik: What you write down is not a group since the subgroup you are trying to take the quotient by is not normal.
Dec 30, 2018 at 4:21 comment added Dima Pasechnik If you can decide this then you can decide whether $F/\langle w_1,...,w_k\rangle$ is trivial, just check for each $w$ being an element of $S$, right? Thus it's undecideable...
Dec 30, 2018 at 3:47 history edited Milo Brandt CC BY-SA 4.0
edited body
Dec 30, 2018 at 3:39 history asked Milo Brandt CC BY-SA 4.0