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Dec 28, 2018 at 22:03 history edited user44191 CC BY-SA 4.0
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Dec 28, 2018 at 21:20 history edited user44191 CC BY-SA 4.0
Expanded on the geometric/group-theoretic idea in YCor's comment
Dec 28, 2018 at 8:08 comment added YCor In a more group-theoretic point of view: $SL(V)$ acts linearly on $V\oplus V^*$. If $\dim(V)\ge 3$, this action has exactly 5 orbits: $\{(0,0)\}$, $(V-\{0\})\oplus\{0\}$, $\{0\}\oplus (V^*-\{0\})$, the set of pairs $(v,\ell)$ such that $v\neq 0$, $\ell(v)=0$, and finally the the set of pairs $(v,\ell)$ such that $\ell(v)\neq 0$. For this latter orbit, the point stabilizer of $(v,\ell)$ preserves the decomposition $Kv\oplus \mathrm{Ker}(\ell)$, fixes $v$ and acts on the hyperplane as an element of determinant 1, so the orbit of $(v,\ell)$ is the required homogeneous space.
Dec 28, 2018 at 4:54 history edited user44191 CC BY-SA 4.0
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Dec 28, 2018 at 4:31 vote accept Question Machine
Dec 28, 2018 at 4:08 history edited user44191 CC BY-SA 4.0
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Dec 28, 2018 at 3:25 history edited user44191 CC BY-SA 4.0
Finished an edit accidentally left half-done, added a new idea
Dec 28, 2018 at 3:20 history edited user44191 CC BY-SA 4.0
Finished an edit accidentally left half-done
Dec 28, 2018 at 3:12 history edited GH from MO CC BY-SA 4.0
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Dec 28, 2018 at 3:11 history answered user44191 CC BY-SA 4.0