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Jan 4, 2019 at 2:02 vote accept Dr. Evil
Dec 31, 2018 at 13:37 answer added Friedrich Knop timeline score: 8
Dec 25, 2018 at 0:50 comment added Victor Protsak There is a well-known classification of representations with free module of coinvariants, due to Vinberg, Popov and Kac. This condition is a priori stronger than freeness of the subalgebra of invariants, but is equivalent to it for "equidimensional" (ED) actions. (A linear representation $V$ of $G$ is ED if all fibers of the quotient map $V\to V/\!/G$ have the same dimension.) An overview with references appears in the volume on geometric invariant theory (Algebraic Geometry 4) of the encyclopaedia of mathematics (green VINITI Russian edition or yellow Springer English translation).
Dec 24, 2018 at 22:22 history asked Dr. Evil CC BY-SA 4.0