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Dec 24, 2018 at 7:36 comment added Denis Nardin @DylanWilson It means the same thing, but that is a theorem, not a definition. See for example these notes, in particular section 4.1. The whole chapter 5 is of course relevant, but I was trying to keep it short :)
Dec 24, 2018 at 7:33 comment added Dylan Wilson Surely HA.5.5.4.10 is also relevant here, unless "factorization algebra" means something different than "factorizable cosheaf on the ran space".
Dec 23, 2018 at 20:14 comment added h__ I saw your correction. No problem. Thank you again.
Dec 23, 2018 at 20:04 history edited Denis Nardin CC BY-SA 4.0
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Dec 23, 2018 at 20:03 comment added Denis Nardin @h__ Embarrassingly I cited the wrong result (in the right section) in the first version of this answer. Please, be sure to check the reference again if you missed the edit. Sorry about it!
Dec 23, 2018 at 19:58 history edited Denis Nardin CC BY-SA 4.0
Clarified how the theorem involves factorization algebras.
Dec 23, 2018 at 19:33 history edited Denis Nardin CC BY-SA 4.0
added 34 characters in body
Dec 23, 2018 at 19:32 history edited Denis Nardin CC BY-SA 4.0
added 34 characters in body
Dec 23, 2018 at 19:31 vote accept h__
Dec 23, 2018 at 19:25 history answered Denis Nardin CC BY-SA 4.0