Timeline for $\mathrm{HH}$ and $\mathrm{HC}$ as two different Taylor expansions at the same point
Current License: CC BY-SA 4.0
5 events
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| Dec 19, 2018 at 19:10 | history | edited | Pedro | CC BY-SA 4.0 |
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| Dec 19, 2018 at 19:06 | comment | added | Pedro | @PhilTosteson Oh, of course. | |
| Dec 19, 2018 at 16:59 | comment | added | Phil Tosteson | Since HH of a free algebra is not concentrated in degree 0, trying to compute it by resolving and abelianizing fails in the simplest case. The left derived functor of an operation is the thing that gives exactly that operation on free algebras. That's one reason why it's HC not HH. | |
| Dec 19, 2018 at 16:00 | history | edited | Pedro | CC BY-SA 4.0 |
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| Dec 19, 2018 at 15:52 | history | asked | Pedro | CC BY-SA 4.0 |