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Jul 14, 2010 at 15:10 history edited David E Speyer CC BY-SA 2.5
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Jul 14, 2010 at 15:05 comment added David E Speyer Any other cool examples of algebraic varieties whose real tangent bundles are stably trivial? The only one that comes to my mind is abelian varieties.
Jul 14, 2010 at 15:04 comment added David E Speyer Let $\alpha_1$, $\alpha_2$, ..., $\alpha_N$ be the Chern roots of $T_{\mathbb{C}} X$. Set $\rho=(1/2) \sum \alpha_i$. So the Todd class is $e^{\rho} \prod T(\alpha_i)$. Now, $\prod T(\alpha_i)$ is a symmetric function of the $\alpha$'s, and is invariant under negating any subset of the $\alpha$'s. So it must be a power series in the elementary symmetric functions of $\alpha_i^2$. However, those are the chern classes of $T_{\mathbb{C}} \oplus T_{\mathbb{C}}^*$, which we just argued were trivial. So, in this setting, the Todd genus is simply $e^{\rho}$.
Jul 14, 2010 at 15:00 comment added David E Speyer Here is an attempt to explain why this happens. Let $X$ be an algebraic variety whose real tangent bundle is stably trivial. $K/T$ has this property, although I'm not sure what the quickest proof is. Writing $T_\mathbb{R}$ and $T_\mathbb{C}$ for the real and holomorphic tangent bundles, we have $T_\mathbb{R} \otimes \mathbb{C} \cong T_{\mathbb{C}} \oplus T_{\mathbb{C}}^*$ (topologically), so the Chern classes of $T_{\mathbb{C}} \oplus T_{\mathbb{C}}^*$ are trivial. (Continued...)
Jul 14, 2010 at 14:45 comment added David E Speyer Here is one of the odd things to note here. The product $\prod_{\alpha \in \Phi^{+}} T(\alpha)$ is $W$-symmetric. By the standard presentation of the cohomology ring of $X$, this means that every high degree term is cohomologically trivial. So we are really just trying to compute $\int_X e^{\mu}$. This partially responds to Bugs' objection that the formula for the Todd genus is messy. (continued...)
Jul 14, 2010 at 14:36 history answered David E Speyer CC BY-SA 2.5