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Jan 26, 2019 at 6:35 vote accept user521337
Dec 16, 2018 at 14:25 answer added Julian Rosen timeline score: 1
Dec 16, 2018 at 3:16 comment added user521337 @JulianRosen: yes, thanks ... I edited ...
Dec 16, 2018 at 3:16 history edited user521337 CC BY-SA 4.0
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Dec 15, 2018 at 22:49 comment added Julian Rosen What is the $k$ that appears in the sum? Also, if you want $\sigma_0+\ldots+\sigma_{p-1}=(x_1+\ldots+x_{q-1})^p$, then I don't see what role the $i$'s are playing in the sum. I might be confused, but did you want something like $\sum_{0\leq j_0\leq p,\ldots,0\leq j_{q-1}\leq p:\sum j_i = p,\sum ij_i\equiv m\mod p} \frac{p!}{j_0!\cdots j_{q-1}!}x_0^{j_0}\cdots x_{q-1}^{j_{q-1}}$?
Dec 15, 2018 at 12:33 history asked user521337 CC BY-SA 4.0