Timeline for Does $f$ have the same minimiser as $\|\nabla f \|$ for $f$ strictly convex?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 13, 2018 at 15:19 | comment | added | David E Speyer | Whoops! You are right, of course. | |
| Dec 13, 2018 at 15:11 | comment | added | fedja | @DavidESpeyer You meant $1\le x+y \le 2$, right? | |
| Dec 13, 2018 at 14:42 | comment | added | David E Speyer | Note also that the same example works on $K = \{ 0 \leq x,y,\ x+y \leq 1 \}$, so requiring that $K$ be full dimensional doesn't help. | |
| Dec 13, 2018 at 13:01 | history | answered | fedja | CC BY-SA 4.0 |