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Dec 13, 2018 at 11:02 comment added Tobias Kildetoft @S.Carnahan Yes.
Dec 13, 2018 at 6:09 comment added S. Carnahan I may be missing something, but doesn't this follow from the fact that the dimension of the weight $\lambda$ subspace of both $M(\lambda)$ and $L(\lambda)$ is one?
Dec 13, 2018 at 3:27 history edited James Cheung CC BY-SA 4.0
added 2 characters in body
Dec 13, 2018 at 3:15 history asked James Cheung CC BY-SA 4.0