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Dec 12, 2018 at 21:34 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 18:25 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 14:50 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 14:49 comment added efs A "not very nice" idea is that your formula should satisfy a recurrence relation. Encode it in a power series, use decomposition into partial fractions and obtain another power series such that its coefficients are the $a_n$; just like for the explicit formula for Fibonacci numbers.
Dec 12, 2018 at 14:46 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 14:24 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 14:19 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 13:48 comment added 1Spectre1 Is it possible to prove result?
Dec 12, 2018 at 13:40 history edited Carlo Beenakker CC BY-SA 4.0
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Dec 12, 2018 at 13:34 comment added Liviu Nicolaescu Why is $a_n=$OEIS A258109?
Dec 12, 2018 at 13:24 history answered Carlo Beenakker CC BY-SA 4.0