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Dec 26, 2018 at 12:15 vote accept Tomás
Dec 22, 2018 at 17:54 answer added Dirk Werner timeline score: 5
Dec 19, 2018 at 17:54 answer added Mikhail Ostrovskii timeline score: 3
Dec 19, 2018 at 10:27 history edited Tomás CC BY-SA 4.0
I wrote a more detailed proof in the particular case where $X$ is finite dimensional.
Dec 16, 2018 at 21:10 comment added Tomás @DirkWerner, I can prove it only when $X$ is finite dimensional. A compactness argument do the work. No idea on how to tackle the infinite dimensional case.
Dec 11, 2018 at 10:10 comment added Tomás In fact, in my proof here I were able to find $\delta>0$ in such a way that $z=-\delta x_0$ worked. But now I see that there is a gap here. Let me try to fix it.
Dec 10, 2018 at 22:22 comment added Dirk Werner Could you explain how to get such a $z$ from just strict convexity?
Dec 10, 2018 at 17:19 history asked Tomás CC BY-SA 4.0