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Dec 8, 2018 at 18:28 comment added Thomas Rot Of course $B(G_1\times G_2)\cong BG_1\times BG_2$. I never read about this, but there are Künneth formulas for bordism groups, I believe due to Landweber here :jstor.org/stable/1994343?seq=1#page_scan_tab_contents . So you might use this to compute things
Dec 8, 2018 at 17:39 history edited wonderich CC BY-SA 4.0
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Dec 8, 2018 at 17:33 history asked wonderich CC BY-SA 4.0