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Timeline for Modular Inequality

Current License: CC BY-SA 2.5

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Jul 14, 2010 at 18:56 vote accept user7551
Jul 13, 2010 at 21:34 answer added James Martin timeline score: 1
Jul 13, 2010 at 15:48 comment added user7551 I'm using a counting measure. $p$ and $q$ are not necessarily co-prime, unfortunately.
Jul 13, 2010 at 15:30 comment added falagar If $p$ and $q$ are coprime you can use Chinese remainder theorem to prove that conditions $a \mod{p} < b \mod{p}$ and $a \mod{q} > b \mod{q}$ are independent.
Jul 13, 2010 at 15:25 comment added Steve Flammia How are you defining the measure?
Jul 13, 2010 at 15:14 history asked user7551 CC BY-SA 2.5