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Dec 6, 2018 at 21:28 comment added Zack Wolske The usual index of an element will be $\sqrt{\text{disc}(\mathbb{Z}[a])/\text{disc}(\mathcal{O}_K)}$. @alpoge By Minkowski arguments, this is bounded above by $|\text{disc}(\mathcal{O}_K)|^{(d-2)/2}$, with some improvements when d=3 or 5, see "Algebraic Integers with Small Discriminant" by Thunder and Wolfskill.
Dec 6, 2018 at 18:08 history asked Stanley Yao Xiao CC BY-SA 4.0