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Dec 8, 2018 at 15:03 history bounty ended Saal Hardali
Dec 8, 2018 at 13:20 history edited Piotr Achinger CC BY-SA 4.0
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Dec 8, 2018 at 12:51 vote accept Saal Hardali
Dec 8, 2018 at 12:51 comment added Saal Hardali Thanks! The answer is more than complete now. Could you point to a specific reference for the positive answer? (the result of Elkik).
Dec 8, 2018 at 12:07 comment added Piotr Achinger Of course! Take $y^2z =x(x-z)(x-\lambda z)$ but in $\mathbb{C}[[x,y,z]]$. There are also plane curve singularity examples, e.g. $xy(x+y)(x-\lambda y)$.
Dec 8, 2018 at 11:18 comment added Saal Hardali Yes, I understand now, of course you are correct, sorry. This covers the proper-smooth case. Do you know a simple example of a surface singularity with a divergent formal deformation? Just to make this answer complete
Dec 8, 2018 at 10:57 comment added Piotr Achinger (I didn't check that in this case $j(\lambda) = 256 (1-\lambda(1-\lambda)^3) \lambda^{-2} (1-\lambda)^{-2}$ is divergent, but most likely it is.)
Dec 8, 2018 at 10:55 comment added Piotr Achinger The answer still stands: take something like $E\colon y^2 z = x(x-z)(x-\lambda z)$ where $\lambda = \sum n! t^n$.
Dec 8, 2018 at 9:25 comment added Saal Hardali I changed the question in hope that it would be more precise so that I could understand the answer. I'm not sure how an elliptic curve can have a divergent $j$-invariant if it comes from a formal deformation. In particular I think both singular affine curves and complete non-singular curves can't be counterexamples. Could you be more precise please? Sorry about the abrupt edit of the question.
Dec 8, 2018 at 9:13 vote accept Saal Hardali
Dec 8, 2018 at 9:13
Dec 7, 2018 at 11:08 vote accept Saal Hardali
Dec 8, 2018 at 9:11
Dec 5, 2018 at 18:18 vote accept Saal Hardali
Dec 5, 2018 at 18:18
Dec 5, 2018 at 18:18 vote accept Saal Hardali
Dec 5, 2018 at 18:18
Dec 5, 2018 at 14:43 history answered Piotr Achinger CC BY-SA 4.0