Timeline for A problem related to the comparison of two integer-valued random variables
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 5, 2018 at 18:17 | comment | added | Andrea Prunotto | I see. Wonderful. Thanks a lot, again! Everything works now! | |
| Dec 5, 2018 at 16:41 | comment | added | Iosif Pinelis | (i) I have added the expression for $P(Y-X>k)$ and the corresponding expression for $E(Y-X)$. (ii) I would not say that $P(Y-X\ge1)$ does not depend on $p_3$, since it depends on $p_1,p_2$, whereas $p_3=1-p_1-p_2$. | |
| Dec 5, 2018 at 16:38 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 551 characters in body
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| Dec 5, 2018 at 6:03 | comment | added | Andrea Prunotto | By the way, it is really surprising to me that $P(Y-X\geq 1)$ does not depend on $p_3$, i .e. on the number of green balls! | |
| Dec 5, 2018 at 5:39 | comment | added | Andrea Prunotto | I wonder if it possible to put somehow together this post and the linked one: the aim would be to find $E[Y-X]=\sum_{k=?}^{\infty}P(Y-K>k)=E[Y]-E[X]$, where the latter terms are the ones you showed in the previous post. The relation $E[Y-X]=E[Y]-E[X]$ should hold for the linearity of the expected value. What do you think? | |
| Dec 4, 2018 at 14:41 | comment | added | Andrea Prunotto | Thanks a lot Iosif! Your answer, and the explicit calculations are really helpful! | |
| Dec 4, 2018 at 14:41 | vote | accept | Andrea Prunotto | ||
| Dec 4, 2018 at 14:36 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |