Timeline for A problem related to the comparison of two integer-valued random variables
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 4, 2018 at 14:41 | vote | accept | Andrea Prunotto | ||
| Dec 4, 2018 at 14:36 | answer | added | Iosif Pinelis | timeline score: 1 | |
| Dec 4, 2018 at 11:46 | comment | added | Andrea Prunotto | @JamesMartin I see. Thank you for your answer. Any suggestion how to evaluate $P(Y-X\geq 1)$ ? | |
| Dec 4, 2018 at 10:45 | comment | added | James Martin | Suppose the first ball drawn is green, the second is red, and the third is blue. Then $X=Y=3$. So no, it is not the case that $P(Y-X\geq 1)=1$. More generally, $X<Y$ if the first green ball drawn comes when a red ball and a blue ball have already been drawn, and otherwise $X=Y$. I would suggest that math.stackexchange.com is a better place than mathoverflow for sorting out this kind of difficulty. | |
| Dec 4, 2018 at 8:44 | history | edited | Andrea Prunotto | CC BY-SA 4.0 |
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| Dec 4, 2018 at 8:38 | history | asked | Andrea Prunotto | CC BY-SA 4.0 |