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Timeline for Acute triangles from 100 points

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Dec 4, 2018 at 21:37 history edited Empy2 CC BY-SA 4.0
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Dec 1, 2018 at 13:05 comment added Empy2 @CarloBeenakker I am pretty sure the MSE answers establish the upper bound of 66.675%, by drawing a contradiction, but don't provide a pattern of points with a slightly lower percentage.
Dec 1, 2018 at 4:08 comment added Gerry Myerson See also math.stackexchange.com/questions/1509657/… and math.stackexchange.com/questions/2892862/… and cut-the-knot.org/Probability/ObtuseTriangle.shtml
Dec 1, 2018 at 2:14 history edited Empy2 CC BY-SA 4.0
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Dec 1, 2018 at 2:01 history edited Adam P. Goucher CC BY-SA 4.0
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Nov 30, 2018 at 23:39 history edited YCor
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Nov 30, 2018 at 22:38 comment added LSpice @NoamD.Elkies, certainly you are right and I am wrong. Despite my quoting it accurately, I read it as "from the 1970's".
Nov 30, 2018 at 22:35 review Close votes
Dec 5, 2018 at 12:35
Nov 30, 2018 at 22:34 comment added Noam D. Elkies @LSpice It's not vague at all. There's only one IMO each year, consisting of six problems. It's easy enough to locate online. Problem 6 reads "In a plane there are $100$ points, no three of which are collinear. Consider all possible triangles having these point as vertices. Prove that no more than $70\%$ of these triangles are acute-angled." artofproblemsolving.com/wiki/index.php?title=1970_IMO_Problems
Nov 30, 2018 at 22:17 history edited Empy2 CC BY-SA 4.0
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Nov 30, 2018 at 22:16 comment added Empy2 Yes, my question iis to fill in the gap between 2/3 and 5/9
Nov 30, 2018 at 22:14 comment added Carlo Beenakker this question is fully answered at math.stackexchange.com/questions/1592964/… .
Nov 30, 2018 at 22:13 history edited Empy2 CC BY-SA 4.0
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Nov 30, 2018 at 22:05 comment added LSpice "An IMO question from 1970" is awfully vague. Could you give more pointers, and/or the statement?
Nov 30, 2018 at 22:02 history asked Empy2 CC BY-SA 4.0