Skip to main content
6 events
when toggle format what by license comment
Nov 30, 2018 at 16:21 history edited Zuhair Al-Johar CC BY-SA 4.0
added 1075 characters in body
Nov 30, 2018 at 15:14 comment added Zuhair Al-Johar @AndrésE.Caicedo yes you are right.
Nov 30, 2018 at 14:26 comment added Andrés E. Caicedo This can be solved the same way you don't like: there are statements P that ZF+V=L does not decide but such that neither P nor not-P increases the strength of the theory. Using P you can cook up two definable sets whose sizes cannot be compared in ZF+V=L but are decided in ZF+V=L+P.
Nov 30, 2018 at 12:33 history edited Zuhair Al-Johar CC BY-SA 4.0
edited title
Nov 30, 2018 at 12:27 history edited Zuhair Al-Johar CC BY-SA 4.0
added 32 characters in body
Nov 30, 2018 at 12:21 history asked Zuhair Al-Johar CC BY-SA 4.0