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Nov 29, 2018 at 11:01 history edited Vladimir Dotsenko CC BY-SA 4.0
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Nov 29, 2018 at 10:55 comment added Vladimir Dotsenko @PeterMueller yes you're right. It makes the argument a little bit more involved - will amend this now.
Nov 29, 2018 at 10:36 comment added Peter Mueller The second sentence isn't quite right. For instance $GL(2,\mathbb Z)$ contains elements of orders $2$ and $3$, so $GL(4,\mathbb Z)$ contains elements of order $6$.
Nov 29, 2018 at 10:27 vote accept Dominic van der Zypen
Nov 29, 2018 at 10:27 history answered Vladimir Dotsenko CC BY-SA 4.0