Timeline for On segments of the series $\sum_p\frac1{p-1}$
Current License: CC BY-SA 4.0
5 events
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Nov 29, 2018 at 7:11 | history | edited | Zhi-Wei Sun | CC BY-SA 4.0 |
added 254 characters in body
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Nov 29, 2018 at 7:05 | history | edited | Zhi-Wei Sun | CC BY-SA 4.0 |
added 254 characters in body
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Nov 29, 2018 at 2:53 | comment | added | Zhi-Wei Sun | See also oeis.org/A261993. | |
Nov 29, 2018 at 2:44 | comment | added | Zhi-Wei Sun | Note that $$\frac1{p_4+1}=\frac1{p_8+1}+\frac1{p_9+1}+\frac1{p_{10}+1}=\frac18$$ and $$\sum_{k=4}^7\frac1{p_k+1}=\sum_{k=5}^{10}\frac1{p_k+1}=\frac{169}{504}.$$ | |
Nov 29, 2018 at 2:22 | history | asked | Zhi-Wei Sun | CC BY-SA 4.0 |