Timeline for "Compactness in measure" in function spaces
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jan 10 at 10:20 | history | edited | YCor | CC BY-SA 4.0 |
formatting
|
Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
|
|
Nov 30, 2018 at 15:21 | vote | accept | Matt R. | ||
Nov 28, 2018 at 23:01 | answer | added | Dirk Werner | timeline score: 2 | |
Nov 28, 2018 at 20:21 | comment | added | Matt R. | @DirkWerner: Those are good comments, and a useful reference. I'll accept them as an answer, if you make one. | |
Nov 28, 2018 at 6:13 | comment | added | Dirk Werner | In my previous comment I meant to say closed, not compact. There are subspaces of $L_1$ with a unit ball that is compact in measure; see G. Godefroy, N. Kalton, D. Li, J. Reine Angew. Math. 471, 43-75 (1996). | |
Nov 27, 2018 at 22:45 | comment | added | Dirk Werner | I guess the authors (who are they anyway?) are talking about the space $S$, also known as $L_0(\mu)$, equipped with the topology of convergence in measure, which can be generated by the metric $d(f,g)=\inf\{\varepsilon>0: \mu\{|f-g|\ge\varepsilon\}\le\varepsilon\}$. Reference to this topology is often made by saying ``in measure'', e.g., one can say that the unit ball of $L_1(\mu)$ is compact in this topology by saying it's compact in measure. | |
Nov 27, 2018 at 16:22 | comment | added | Nate Eldredge | Then I'm confused how this is a norm. If $V$ has measure, say, 3, then no function could have norm greater than 3 (taking $s \to 0$). So it can't be homogeneous. Am I missing something? | |
Nov 27, 2018 at 15:49 | comment | added | Matt R. | Yes, the inf is over $s$; I've fixed that. This topic comes up in the section on $L^p(V)$, where $V$ is a set of finite Lebesgue measure in a finite-dimensional space. | |
Nov 27, 2018 at 15:46 | history | edited | Matt R. | CC BY-SA 4.0 |
edited body
|
Nov 27, 2018 at 15:36 | comment | added | Nate Eldredge | Is the inf supposed to be over $s$? Are we working on any particular measure space, or a general one? I guess it has to be an infinite measure space? | |
Nov 27, 2018 at 15:35 | review | First posts | |||
Nov 27, 2018 at 15:44 | |||||
Nov 27, 2018 at 15:32 | history | asked | Matt R. | CC BY-SA 4.0 |