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ThiKu
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The easiest counterexample is the Riemannian product $$F\times M$$$$M=F\times N$$ for $F$ a manifold of constant non-zero sectional curvature and $N$ an arbitrary Riemannian manifold of dimension $n-k$. ($M$ is foliated by the copies of $F$.)

Any plane that is the product of a line in $F$ with a line in $M$$N$ will be locally isometric to ${\mathbb R}^2$ and thus have sectional curvature equal to zero.

So the sectional curvature is not constant, even if the sectional curvature of $M$$N$ were the same as that of $F$. (Which of course needn‘t be the case anyway.)

The easiest counterexample is the product $$F\times M$$ for $F$ a manifold of constant non-zero sectional curvature.

Any plane that is the product of a line in $F$ with a line in $M$ will have sectional curvature equal to zero.

So the sectional curvature is not constant, even if the sectional curvature of $M$ were the same as that of $F$. (Which of course needn‘t be the case anyway.)

The easiest counterexample is the Riemannian product $$M=F\times N$$ for $F$ a manifold of constant non-zero sectional curvature and $N$ an arbitrary Riemannian manifold of dimension $n-k$. ($M$ is foliated by the copies of $F$.)

Any plane that is the product of a line in $F$ with a line in $N$ will be locally isometric to ${\mathbb R}^2$ and thus have sectional curvature equal to zero.

So the sectional curvature is not constant, even if the sectional curvature of $N$ were the same as that of $F$. (Which of course needn‘t be the case anyway.)

Source Link
ThiKu
  • 10.4k
  • 2
  • 38
  • 63

The easiest counterexample is the product $$F\times M$$ for $F$ a manifold of constant non-zero sectional curvature.

Any plane that is the product of a line in $F$ with a line in $M$ will have sectional curvature equal to zero.

So the sectional curvature is not constant, even if the sectional curvature of $M$ were the same as that of $F$. (Which of course needn‘t be the case anyway.)