Skip to main content
13 events
when toggle format what by license comment
Nov 28, 2018 at 6:28 comment added Harry Altman So this is interesting -- it seems like Thue-Morse doesn't consistently do better than alternating (or "snaking", i.e. repeating $0110$ over and over), but reverse Thue-Morse looks like it consistently does better than all of these, even though it's not the minimum.
Nov 28, 2018 at 5:27 comment added Harry Altman Huh, so it's not unique. I wasn't expecting an answer there so fast! But now with Raphael's recursion it's easy. I'll have to go write a thing to compute that so I can try some other things with this. Thanks again!
Nov 27, 2018 at 23:26 comment added Claude Chaunier The fairest difference for $n=16$ is $0$ as it is for $n=6$. What is the next such $n$ ?
Nov 27, 2018 at 22:17 history edited Claude Chaunier CC BY-SA 4.0
added 439 characters in body
Nov 27, 2018 at 14:03 history edited Claude Chaunier CC BY-SA 4.0
added scores of Thue-Morse, reverse Thue-Morse and alternating sequences for n up to 17
Nov 27, 2018 at 6:44 comment added Claude Chaunier ok, I'll do it. I wonder if other weights than $0,1,\dots,n$ makes the Thue-Morse the fairest.
Nov 27, 2018 at 6:43 history edited Claude Chaunier CC BY-SA 4.0
added n=14 and its fairest sequences
Nov 27, 2018 at 3:52 comment added Harry Altman Well, OK! If you're already planning to do more computation, do you mind if I ask you also: Just how close do Thue-Morse and reverse Thue-Morse come? Thanks!
Nov 26, 2018 at 20:53 history edited Claude Chaunier CC BY-SA 4.0
added 535 characters in body
Nov 26, 2018 at 8:27 comment added Claude Chaunier @HarryAlman You may wait a few more days as well. And I'll improve on brute-force. Any consecutive run of $k$ random strikes could easily take $k!$ times less time. And computing upper and lower bounds on the values to expect after some binary prefix might help ruling it out before trying to lengthen it.
Nov 26, 2018 at 6:02 comment added Harry Altman Thanks! Heh, guess I should've tried brute-forcing before asking; oh well. Anyway, this is interesting. Doesn't match TM or reverse TM unless $n\le 4$, it seems; it looks a little closer to reverse though? (For $n=3$, it matches that, but I could've told you that.) There's an obvious followup question here, which is "Is this always unique for $n$ odd?" -- but that's clearly a separate question. Anyway, going to wait a day to see if other answers, otherwise I'll accept this, because this does seem to answer my question. Meanwhile going to play around with this some. :)
Nov 26, 2018 at 5:06 history edited Claude Chaunier CC BY-SA 4.0
increased $n$ to $11$
Nov 26, 2018 at 0:35 history answered Claude Chaunier CC BY-SA 4.0