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Aug 26, 2020 at 4:17 comment added Nick S If $f$ is almost periodic and $f(tz) = f(z)$ then the Fourier--Bohr coefficients are invariant under rotations. But the Fourier--Bohr coefficients are zero outside a countable set, therefore only the FB coefficient at 0 can be non-zero, i.e. $f$ is constant.
Nov 24, 2018 at 1:30 answer added Nik Weaver timeline score: 6
Nov 24, 2018 at 0:23 history edited Arun Debray CC BY-SA 4.0
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Nov 24, 2018 at 0:15 review First posts
Nov 24, 2018 at 0:23
Nov 24, 2018 at 0:13 history asked Merry CC BY-SA 4.0