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Nov 29, 2018 at 16:01 history bounty ended CommunityBot
Nov 22, 2018 at 21:41 comment added Carlo Beenakker @lcv --- no, I have never seen a formula with all the Kronecker delta's explicitly printed out for more than 4 unitaries; such calculations quickly get tedious; there exists a Mathematica package
Nov 22, 2018 at 19:24 comment added Marcel @lcv that is what I called "Weingarten calculus". You can search for "Weingarten functions". For 8 U's, four of them being conjugated, you get a sum over all 24 elements of the permutation group $S_4$.
Nov 22, 2018 at 19:04 comment added lcv @Carlo Beenakker do you have a reference for an analogous formula with 8 $U$’s? (Written in such a simple way)
Nov 22, 2018 at 17:55 history edited Carlo Beenakker CC BY-SA 4.0
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Nov 22, 2018 at 17:46 comment added Carlo Beenakker I added the identity that I applied to the integral over the product of traces.
Nov 22, 2018 at 17:45 history edited Carlo Beenakker CC BY-SA 4.0
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Nov 22, 2018 at 17:22 comment added Marcel Did you write the trace in terms of matrix elements and then used Weingarten calculus?
Nov 22, 2018 at 17:15 comment added Marcel Interesting. Might I ask about the method?
Nov 22, 2018 at 12:08 history edited Carlo Beenakker CC BY-SA 4.0
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Nov 22, 2018 at 11:31 history answered Carlo Beenakker CC BY-SA 4.0