Timeline for When the action on cohomology is trivial?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 4, 2019 at 13:51 | history | edited | Shivani Sengupta | CC BY-SA 4.0 |
deleted 336 characters in body; edited title
|
| Nov 27, 2018 at 17:19 | comment | added | user43326 | In that case $H^*(X,Z/2)$ is naturally isomorphic to $H^*(X,Z)\otimes Z/2$, so $g_{Z/2}^*=g_Z^*\otimes Z/2$. | |
| Nov 26, 2018 at 13:38 | history | edited | Shivani Sengupta | CC BY-SA 4.0 |
deleted 38 characters in body
|
| S Nov 24, 2018 at 18:06 | history | suggested | user43326 | CC BY-SA 4.0 |
The word "trivial" is misleading here, because the reader would think of zero, not of the identity.
|
| Nov 24, 2018 at 14:56 | review | Suggested edits | |||
| S Nov 24, 2018 at 18:06 | |||||
| Nov 24, 2018 at 14:53 | comment | added | user43326 | A trivial sufficient condition: when $H^*(X,Z)$ is torsion-free. | |
| Nov 22, 2018 at 10:31 | history | edited | Qfwfq | CC BY-SA 4.0 |
deleted 4 characters in body; edited title
|
| Nov 22, 2018 at 10:00 | answer | added | Neil Strickland | timeline score: 7 | |
| Nov 22, 2018 at 8:38 | history | asked | Shivani Sengupta | CC BY-SA 4.0 |