Skip to main content
9 events
when toggle format what by license comment
Nov 22, 2018 at 21:18 comment added shurtados @GerryMyerson: Thanks for the observation. I'm more interested in the random case, when the size of $A, B$ is comparable to $n$, and even for more general choices of $x_i$, but always keeping $x_i$ very small compared to $n$.
Nov 22, 2018 at 15:01 comment added shurtados @Seva: Yes, that's what I want. I modified the statement to make it hopefully more clear.
Nov 22, 2018 at 14:58 history edited shurtados CC BY-SA 4.0
added 140 characters in body
Nov 22, 2018 at 11:57 comment added Gerry Myerson Write $S_n=A-B$, where $A$ collects all the $+1$ terms, $B$, all the $-1$ terms. Then $S+2B=A+B=0$, so $B=-(1/2)S$, so $S$ is tiny if and only if $B$ is tiny. So I don't think "taking all the roots of unity" makes the problem any easier than taking any old sum of $n$th roots of unity.
Nov 22, 2018 at 10:10 comment added Seva What do you mean writing "given that there are $2^n$ sums, I am expecting a better lower bound"? Don't you need a uniform lower bound for all these sums? That is, do you want to show that none of the $2^n$ sums are small in absolute value?
Nov 22, 2018 at 6:36 history edited shurtados
edited tags
Nov 22, 2018 at 0:28 comment added shurtados Thank you, I saw that while writing the question, so it seems the question is very difficult, my hope is that because I'm taking all the roots of unity something different can be said, for example when $x_i$ are characters, the absolute value of the sum is $\sqrt(p)$ (If I'm correct).
Nov 22, 2018 at 0:16 comment added Mark Lewko See: mathoverflow.net/questions/46068/… for a related discussion.
Nov 22, 2018 at 0:08 history asked shurtados CC BY-SA 4.0