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Nov 23, 2018 at 12:18 comment added Vladimir Dotsenko @abx more specifically to this argument, monomials are orthogonal but not orthonormal, and for a monomial $M$, the pairing $\langle M,M\rangle$ vanishes in characteristic $p$ if $p$ is less than or equal to one of the exponents of $M$.
Nov 22, 2018 at 7:12 comment added abx Right, thanks. This is needed for the duality between symmetric powers.
Nov 21, 2018 at 22:07 comment added Mizar @abx I think the argument needs a field of characteristic 0, or at least characteristic not dividing $(m+n)!$ (here $n$ is not the number of variables)
Nov 21, 2018 at 17:27 comment added abx Nice, thanks! In fact that works over any field, you just need to view $R(\partial )$ as an element of $V_n^{*}$.
Nov 21, 2018 at 17:24 vote accept abx
Nov 21, 2018 at 15:51 history answered fedja CC BY-SA 4.0