Timeline for Effective Bertini
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 20, 2018 at 20:37 | comment | added | Giulio | Just to make things more explicit, I am interested in the case $q>>0$. Moreover, let me explain a little computation to justify my last guess about the complement of $V_q$. Take $X=\mathbb{P}^2$, and $L=\mathcal{O}(3)$. Fix a line $H$, multiplying by $(q+1)H$ we can embed $| \mathcal{O}(2q-1)|$ into the complement of $V_q$. My guess is that this is kind of the biggest thing that can be outside $V_q$ (but I have no proof for the moment). | |
| Nov 20, 2018 at 14:47 | answer | added | David E Speyer | timeline score: 6 | |
| Nov 20, 2018 at 14:43 | comment | added | Giulio | Thanks! My main issue is with $V_q$. | |
| Nov 20, 2018 at 14:41 | comment | added | Jason Starr | For all $q\geq q_0$, the complement of $U_q$ is a divisor whose degree is known, cf. mathoverflow.net/questions/165672/… Replace $\mathcal{O}(1)$ in that answer by an appropriately positive tensor power of $L$, and use the asymptotic formula to find $q_0$. | |
| Nov 20, 2018 at 14:29 | history | asked | Giulio | CC BY-SA 4.0 |