Timeline for The roots of unity in a tensor product of commutative rings
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Nov 19, 2018 at 22:58 | history | edited | user131093 | CC BY-SA 4.0 |
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| Nov 18, 2018 at 5:23 | comment | added | user131093 | You are (both) completely correct --- my computations on scribble paper on the bus were nonsense | |
| Nov 18, 2018 at 5:20 | history | edited | user131093 | CC BY-SA 4.0 |
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| Nov 18, 2018 at 4:32 | comment | added | YCor | I agree that in this case, $[G,G]=[G,[G,G]]$ (a normal subgroup of order 27). | |
| Nov 18, 2018 at 4:14 | comment | added | David E Speyer | I am confused. I see that $[V,V]$, in your example, is the order 3 subgroup you describe. But it looks to me like $[G,V] = V$, which makes your example trivial. | |
| Nov 18, 2018 at 3:38 | comment | added | David E Speyer | Wow! That is quite a computation. I'll try to get my argument for this part written up tonight or tomorrow night. | |
| Nov 18, 2018 at 3:22 | history | answered | user131093 | CC BY-SA 4.0 |