Timeline for Finite nonabelian groups of odd order
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 2, 2023 at 2:42 | history | edited | Wlod AA | CC BY-SA 4.0 |
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| Jul 14, 2010 at 4:41 | answer | added | Amitesh Datta | timeline score: 8 | |
| Jul 14, 2010 at 4:01 | comment | added | Amitesh Datta | @Gerald Edgar Groups of order $p^2$ for $p$ prime are always abelian and hence your comment can be easily generalized. | |
| Jul 12, 2010 at 16:58 | vote | accept | falagar | ||
| Jul 12, 2010 at 16:51 | comment | added | Pete L. Clark | This appears to be an exact duplicate of mathoverflow.net/questions/11001/… | |
| Jul 12, 2010 at 14:34 | comment | added | Johannes Hahn | The answer is easy with sylows theorems. Use that there are nonabelian groups of order $p^3$ for every prime and look at all prime factorizations with exponents $\leq 2$. For such $n$, the conditions of sylow for normality of all the sylow-groups are necessary and sufficient for all groups of order $n$ being abelian. | |
| Jul 12, 2010 at 14:29 | answer | added | Robin Chapman | timeline score: 38 | |
| Jul 12, 2010 at 14:14 | comment | added | Gerald Edgar | n=4 no nonabelian group. Also n=2 of course. | |
| Jul 12, 2010 at 14:06 | history | asked | falagar | CC BY-SA 2.5 |