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Nov 17, 2018 at 3:22 answer added Brendan McKay timeline score: 3
Nov 16, 2018 at 21:50 comment added Ilya Bogdanov On the other hand, if $n$ is even, then any $n$-cycle is odd, hence the graph is bipartite, and there is no triangle in it.
Nov 16, 2018 at 19:34 comment added Ilya Bogdanov This argument shows also that a subgraph on $\Omega(n)$ vertices cannot have edge density $1-o(1)$.
Nov 16, 2018 at 19:29 history edited Wei Zhan CC BY-SA 4.0
added 258 characters in body
Nov 16, 2018 at 19:29 comment added Ilya Bogdanov If $n$ is prime, then tge powers of one cycle form a largest size clique. Ondeed, among $n+1$ permutations, two send $1$ to the same element, hence they dp not differ by an $n$-cycle.
Nov 16, 2018 at 17:39 history edited Martin Sleziak
added the (cayley-graphs) tag
Nov 16, 2018 at 17:29 history asked Wei Zhan CC BY-SA 4.0