Timeline for Show that if $p\neq 2$, then $\mathbb{Z}_p$ cannot act freely on $\mathbb{C}P^n$
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 19, 2018 at 14:23 | vote | accept | Shivani Sengupta | ||
| Nov 17, 2018 at 6:10 | comment | added | Shivani Sengupta | @scarmeli Instead of taking $CP^n$ if we take $Y = CP^{n_1} \times CP^{n_2} \times ... \times CP^{n_k}$, then how to show that $Z_p$ does not act freely on $Y$ using spectral sequence where $p\neq 2 $? I have edited the question. Please have a look. | |
| Nov 16, 2018 at 13:25 | history | answered | S. carmeli | CC BY-SA 4.0 |