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Nov 13, 2018 at 17:40 vote accept Noah Riggenbach
Nov 13, 2018 at 16:48 answer added Denis Nardin timeline score: 9
Nov 13, 2018 at 15:57 comment added Noah Riggenbach @DenisNardin I understand why both operations separately are $A^\infty$, I just don't understand the distributivity I suppose.
Nov 13, 2018 at 15:54 history edited Noah Riggenbach CC BY-SA 4.0
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Nov 13, 2018 at 15:49 comment added Denis Nardin Uh, I might be a bit confused, but $\Omega^\infty\Sigma^\infty_+ |G|$ is certainly an $A_\infty$-ring
Nov 13, 2018 at 15:45 review First posts
Nov 13, 2018 at 15:57
Nov 13, 2018 at 15:41 history asked Noah Riggenbach CC BY-SA 4.0