Timeline for Noetherian spectral space comes from noetherian ring?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 10, 2019 at 7:35 | comment | added | user141498 | relevant: mathoverflow.net/a/330735/141498 | |
| Nov 10, 2018 at 20:40 | vote | accept | Hans | ||
| Nov 10, 2018 at 20:03 | comment | added | Pierre-Yves Gaillard | @KarlSchwede - You may want to take look at my comment below. | |
| Nov 10, 2018 at 19:55 | answer | added | David Lampert | timeline score: 9 | |
| Nov 10, 2018 at 18:31 | comment | added | Karl Schwede | I wonder if Hochster's thesis addresses this? Off the top of my head, I don't know how to make the following Noetherian topological space $\{p,q,r\}$, with open sets $\{ \{p,q,r\}, \{p,q\}, \{p\} \}$, as the spectrum of a Noetherian ring (it's the spectrum of the non-discrete valuation ring associated to $\mathbb{Z} \times \mathbb{Z}$ with the lex order). | |
| Nov 10, 2018 at 18:21 | comment | added | Qfwfq | Oh yes, you're totally right, it's the underlying top space of the Spec not the scheme | |
| Nov 10, 2018 at 18:19 | comment | added | Qfwfq | $\mathrm{Spec}$ is an (anti-)equivalence from commutative rings to affine scheme, so two rings are isomorphic iff their Spec's are. So, if such a noetherian $B$ exists, your $A$ was already isomorphic to it. | |
| Nov 10, 2018 at 18:17 | history | edited | მამუკა ჯიბლაძე | CC BY-SA 4.0 |
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| Nov 10, 2018 at 18:05 | history | asked | Hans | CC BY-SA 4.0 |