Skip to main content
4 events
when toggle format what by license comment
Nov 10, 2018 at 12:40 vote accept Mare
Nov 10, 2018 at 12:22 comment added Jeremy Rickard @Mare Yes, $\widehat{\text{Ext}}^0$ is stable $\text{Hom}$.
Nov 10, 2018 at 12:17 comment added Mare Thanks. One question: Is $\hat{Ext_B}^0(X,M))=\underline{Hom_B}(X,M)$? Ill try my luck a bit to look for question 2 with $B=K<x,y>/(x^2,y^2,xy-qyx)$ since there such modules $M$ exists when q is not a root of unity and maybe in some cases there can be only finitely many such X, at least it looks like a very strong condition that this ext vanishes for all $i \in \mathbb{Z}$.
Nov 10, 2018 at 11:59 history answered Jeremy Rickard CC BY-SA 4.0