Timeline for Jacobson radical of a tensor product
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 8, 2018 at 7:41 | comment | added | Mare | @YCor Yes, I meant perfect. | |
| Nov 7, 2018 at 23:01 | comment | added | YCor | @Mare what do you call a separable field? a perfect field? | |
| Nov 7, 2018 at 21:01 | comment | added | Mare | In general I think there is nothing useful known, but in some special situations we have $rad(A_1 \otimes_R A_2)=rad(A_1) \otimes_R A_2 + A_1 \otimes_R rad(A_2)$. For example when $A_i$ are finite dimensional over a seperable field R. | |
| Nov 7, 2018 at 20:45 | comment | added | abx | If $L/K$ is a purely inseparable extension of fields, the radical of $L\otimes _KL$ is nonzero while that of $L$ is of course zero. This leaves little hope to find a general expression for the radical of a tensor product. | |
| Nov 7, 2018 at 19:02 | history | asked | Paul Broussous | CC BY-SA 4.0 |