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According to this researchthis search in $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$sigma product of incountably many copies of $\mathbb{R}$ (no longer in pi-Base as of 2023 March) and the boolean product topology on $\mathbb{R}^{\omega}$boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

According to this research in $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

According to this search in $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ (no longer in pi-Base as of 2023 March) and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

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Francesco Polizzi
  • 66.3k
  • 5
  • 180
  • 283

According to this research toin $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

According to this research to $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

According to this research in $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.

Source Link
Francesco Polizzi
  • 66.3k
  • 5
  • 180
  • 283

According to this research to $\pi$-base, the sigma product of incountably many copies of $\mathbb{R}$ and the boolean product topology on $\mathbb{R}^{\omega}$ are connected, $T_2$ and homogeneous.

However, they are not first countable, hence they cannot be homeomorphic to subspaces of $\mathbb{R}^{\omega}$.