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Nov 6, 2018 at 9:02 answer added KP Hart timeline score: 4
Nov 5, 2018 at 15:58 vote accept Dominic van der Zypen
Nov 5, 2018 at 15:43 answer added Francesco Polizzi timeline score: 2
Nov 5, 2018 at 15:17 comment added Nate Eldredge How about the weak topology on a separable Banach space? It's not metrizable nor even first countable, so can't be homeomorphic to any subspace of $\mathbb{R}^\omega$.
Nov 5, 2018 at 15:10 history asked Dominic van der Zypen CC BY-SA 4.0