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Nov 6, 2018 at 8:18 comment added Per Alexandersson I believe (9.4) in Macdonald's book, p.143 is something like that - I remember thinking about this a while ago, and I think I found quite an easy bijection...
Nov 6, 2018 at 6:18 comment added s_nrsw @Timothy Chow Thank you for you guide. would you know if there is a bijection proof of this formula?
Nov 6, 2018 at 6:00 comment added s_nrsw @Per Alexandersson Thank you. The answer is probably what I want to know (I still don't have completely understanding). By the way, is there a bijection proof of this formula ?
Nov 6, 2018 at 4:13 history edited s_nrsw CC BY-SA 4.0
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Nov 6, 2018 at 4:10 comment added s_nrsw @ darij grinberg I defined $\tau_i$ and $\sigma_i$ as entries of a prtition, namely Set $\mu = (\mu_1, \mu_2, \dots, \mu_k)$, then we define $\tau = (\tau_1, \dots, \tau_k)$, $\sigma = (\sigma_1, \dots, \sigma_{k-1})$. where $\tau_i = (\mu_i + \mu_{i+1} +\cdots)$, $\sigma_i = (\mu_{i+1} + \mu_{i+2} +\cdots)$. Thank you for your pointing it out, I have modified the question.
Nov 5, 2018 at 17:16 comment added darij grinberg What do you mean by "$\tau_i = (\mu_{i}, \mu_{i+1},\dots), \sigma_i = (\mu_{i+1}, \mu_{i+2},\dots)$"? Either you're defining partitions or you're defining entries of a partition.
Nov 5, 2018 at 17:11 history edited Martin Sleziak
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Nov 5, 2018 at 16:10 review Close votes
Nov 21, 2018 at 22:34
Nov 5, 2018 at 15:53 comment added Timothy Chow Possible duplicate of Skew Kostka coefficients from Littlewood-Richardson Coefficients
Nov 5, 2018 at 13:17 comment added Per Alexandersson That's a good question. There is an excellent answer by R. Stanley to a more general question here: mathoverflow.net/questions/116171/…
Nov 5, 2018 at 12:04 history edited s_nrsw CC BY-SA 4.0
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Nov 5, 2018 at 11:55 review First posts
Nov 5, 2018 at 12:00
Nov 5, 2018 at 11:50 history asked s_nrsw CC BY-SA 4.0