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Nov 4, 2018 at 23:40 history edited Matt Samuel CC BY-SA 4.0
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Nov 4, 2018 at 17:32 comment added Matt Samuel @oui I finished the proof for completeness. It doesn't use symmetry of the word.
Nov 4, 2018 at 17:31 history edited Matt Samuel CC BY-SA 4.0
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Nov 4, 2018 at 16:30 comment added ouimerci Well, I think this answers my question then!
Nov 4, 2018 at 16:29 vote accept ouimerci
Nov 4, 2018 at 16:24 comment added Matt Samuel @ouimerci That's right, I prove that such a word exists.
Nov 4, 2018 at 16:23 comment added ouimerci So, you're showing that for any root $\beta$, $s_\beta$ can be written with a symmetric word of length $2\mathrm{dp}(\beta) -1$, right? Then, to answer the question/claim in my post, you'd essentially combine that with the equality written there. I'm not sure of what you assume and what you conclude. (And thanks!)
Nov 4, 2018 at 15:20 history edited Matt Samuel CC BY-SA 4.0
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Nov 4, 2018 at 15:03 history answered Matt Samuel CC BY-SA 4.0